11y^2-10y-14=0

Solution for 11y^2-10y-14=0 equation:

11y^2-10y-14=0

a = 11; b = -10; c = -14;
Δ = b2-4ac
Δ = -102-4·11·(-14)
Δ = 716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{716}=\sqrt{4*179}=\sqrt{4}*\sqrt{179}=2\sqrt{179}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{179}}{2*11}=\frac{10-2\sqrt{179}}{22}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{179}}{2*11}=\frac{10+2\sqrt{179}}{22}
$